Snippet #1

\nabla=\frac{\Delta}{\nabla}

Since \Delta v=\langle\nabla, \nabla v\rangle =\nabla \cdot \nabla v = \nabla^2 v and thus \Delta=\nabla^2 is common abuse of notation, I propose this formal identity.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.